The xpath() method

For ElementTree, the xpath method performs a global XPath query against the document (if absolute) or against the root node (if relative):

>>> f = StringIO('<foo><bar></bar></foo>')
>>> tree = etree.parse(f)

>>> r = tree.xpath('/foo/bar')
>>> len(r)
1
>>> r[0].tag
'bar'

>>> r = tree.xpath('bar')
>>> r[0].tag
'bar'

When xpath() is used on an Element, the XPath expression is evaluated against the element (if relative) or against the root tree (if absolute):

>>> root = tree.getroot()
>>> r = root.xpath('bar')
>>> r[0].tag
'bar'

>>> bar = root[0]
>>> r = bar.xpath('/foo/bar')
>>> r[0].tag
'bar'

>>> tree = bar.getroottree()
>>> r = tree.xpath('/foo/bar')
>>> r[0].tag
'bar'

The xpath() method has support for XPath variables:

>>> expr = "//*[local-name() = $name]"

>>> print root.xpath(expr, name = "foo")[0].tag
foo

>>> print root.xpath(expr, name = "bar")[0].tag
bar

>>> print root.xpath("$text", text = "Hello World!")
Hello World!

Optionally, you can provide a namespaces keyword argument, which should be a dictionary mapping the namespace prefixes used in the XPath expression to namespace URIs:

>>> f = StringIO('''\
... <a:foo xmlns:a="http://codespeak.net/ns/test1"
...        xmlns:b="http://codespeak.net/ns/test2">
...    <b:bar>Text</b:bar>
... </a:foo>
... ''')
>>> doc = etree.parse(f)

>>> r = doc.xpath('/t:foo/b:bar',
...               namespaces={'t': 'http://codespeak.net/ns/test1',
...                           'b': 'http://codespeak.net/ns/test2'})
>>> len(r)
1
>>> r[0].tag
'{http://codespeak.net/ns/test2}bar'
>>> r[0].text
'Text'

There is also an optional extensions argument which is used to define custom extension functions in Python that are local to this evaluation.

XPath return values

The return values of XPath evaluations vary, depending on the XPath expression used:

• True or False, when the XPath expression has a boolean result
• a float, when the XPath expression has a numeric result (integer or float)
• a 'smart' string (as described below), when the XPath expression has a string result.
• a list of items, when the XPath expression has a list as result. The items may include Elements (also comments and processing instructions), strings and tuples. Text nodes and attributes in the result are returned as 'smart' string values. Namespace declarations are returned as tuples of strings: (prefix, URI).

XPath string results are 'smart' in that they provide a getparent() method that knows their origin:

• for attribute values, result.getparent() returns the Element that carries them. An example is //foo/@attribute, where the parent would be a foo Element.
• for the text() function (as in //text()), it returns the Element that contains the text or tail that was returned.

You can distinguish between different text origins with the boolean properties is_text, is_tail and is_attribute.

Note that getparent() may not always return an Element. For example, the XPath functions string() and concat() will construct strings that do not have an origin. For them, getparent() will return None.

Generating XPath expressions

ElementTree objects have a method getpath(element), which returns a structural, absolute XPath expression to find that element:

>>> a  = etree.Element("a")
>>> b  = etree.SubElement(a, "b")
>>> c  = etree.SubElement(a, "c")
>>> d1 = etree.SubElement(c, "d")
>>> d2 = etree.SubElement(c, "d")

>>> tree = etree.ElementTree(c)
>>> print tree.getpath(d2)
/c/d[2]
>>> tree.xpath(tree.getpath(d2)) == [d2]
True

The XPath class

The XPath class compiles an XPath expression into a callable function:

>>> root = etree.XML("<root><a><b/></a><b/></root>")

>>> find = etree.XPath("//b")
>>> print find(root)[0].tag
b

The compilation takes as much time as in the xpath() method, but it is done only once per class instantiation. This makes it especially efficient for repeated evaluation of the same XPath expression.

Just like the xpath() method, the XPath class supports XPath variables:

>>> count_elements = etree.XPath("count(//*[local-name() = $name])")

>>> print count_elements(root, name = "a")
1.0
>>> print count_elements(root, name = "b")
2.0

This supports very efficient evaluation of modified versions of an XPath expression, as compilation is still only required once.

Prefix-to-namespace mappings can be passed as second parameter:

>>> root = etree.XML("<root xmlns='NS'><a><b/></a><b/></root>")

>>> find = etree.XPath("//n:b", namespaces={'n':'NS'})
>>> print find(root)[0].tag
{NS}b

By default, XPath supports regular expressions in the EXSLT namespace:

>>> regexpNS = "http://exslt.org/regular-expressions"
>>> find = etree.XPath("//*[re:test(., '^abc$', 'i')]",
...                    namespaces={'re':regexpNS})

>>> root = etree.XML("<root><a>aB</a><b>aBc</b></root>")
>>> print find(root)[0].text
aBc

You can disable this with the boolean keyword argument regexp which defaults to True.

The XPathEvaluator classes

lxml.etree provides two other efficient XPath evaluators that work on ElementTrees or Elements respectively: XPathDocumentEvaluator and XPathElementEvaluator. They are automatically selected if you use the XPathEvaluator helper for instantiation:

>>> root = etree.XML("<root><a><b/></a><b/></root>")
>>> xpatheval = etree.XPathEvaluator(root)

>>> print isinstance(xpatheval, etree.XPathElementEvaluator)
True

>>> print xpatheval("//b")[0].tag
b

This class provides efficient support for evaluating different XPath expressions on the same Element or ElementTree.

ETXPath

ElementTree supports a language named ElementPath in its find*() methods. One of the main differences between XPath and ElementPath is that the XPath language requires an indirection through prefixes for namespace support, whereas ElementTree uses the Clark notation ({ns}name) to avoid prefixes completely. The other major difference regards the capabilities of both path languages. Where XPath supports various sophisticated ways of restricting the result set through functions and boolean expressions, ElementPath only supports pure path traversal without nesting or further conditions. So, while the ElementPath syntax is self-contained and therefore easier to write and handle, XPath is much more powerful and expressive.

lxml.etree bridges this gap through the class ETXPath, which accepts XPath expressions with namespaces in Clark notation. It is identical to the XPath class, except for the namespace notation. Normally, you would write:

>>> root = etree.XML("<root xmlns='ns'><a><b/></a><b/></root>")

>>> find = etree.XPath("//p:b", namespaces={'p' : 'ns'})
>>> print find(root)[0].tag
{ns}b

ETXPath allows you to change this to:

>>> find = etree.ETXPath("//{ns}b")
>>> print find(root)[0].tag
{ns}b

Error handling

lxml.etree raises exceptions when errors occur while parsing or evaluating an XPath expression:

>>> find = etree.XPath("\\")
Traceback (most recent call last):
  ...
XPathSyntaxError: Invalid expression

lxml will also try to give you a hint what went wrong, so if you pass a more complex expression, you may get a somewhat more specific error:

>>> find = etree.XPath("//*[1.1.1]")
Traceback (most recent call last):
  ...
XPathSyntaxError: Invalid predicate

During evaluation, lxml will emit an XPathEvalError on errors:

>>> find = etree.XPath("//ns:a")
>>> find(root)
Traceback (most recent call last):
  ...
XPathEvalError: Undefined namespace prefix

This works for the XPath class, however, the other evaluators (including the xpath() method) are one-shot operations that do parsing and evaluation in one step. They therefore raise evaluation exceptions in all cases:

>>> root = etree.Element("test")
>>> find = root.xpath("//*[1.1.1]")
Traceback (most recent call last):
  ...
XPathEvalError: Invalid predicate

>>> find = root.xpath("//ns:a")
Traceback (most recent call last):
  ...
XPathEvalError: Undefined namespace prefix

>>> find = root.xpath("\\")
Traceback (most recent call last):
  ...
XPathEvalError: Invalid expression

Note that lxml versions before 1.3 always raised an XPathSyntaxError for all errors, including evaluation errors. The best way to support older versions is to except on the superclass XPathError.

XSLT result objects

The result of an XSL transformation can be accessed like a normal ElementTree document:

>>> f = StringIO('<a><b>Text</b></a>')
>>> doc = etree.parse(f)
>>> result = transform(doc)

>>> result.getroot().text
'Text'

but, as opposed to normal ElementTree objects, can also be turned into an (XML or text) string by applying the str() function:

>>> str(result)
'<?xml version="1.0"?>\n<foo>Text</foo>\n'

The result is always a plain string, encoded as requested by the xsl:output element in the stylesheet. If you want a Python unicode string instead, you should set this encoding to UTF-8 (unless the ASCII default is sufficient). This allows you to call the builtin unicode() function on the result:

>>> unicode(result)
u'<?xml version="1.0"?>\n<foo>Text</foo>\n'

You can use other encodings at the cost of multiple recoding. Encodings that are not supported by Python will result in an error:

>>> xslt_tree = etree.XML('''\
... <xsl:stylesheet version="1.0"
...     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
...     <xsl:output encoding="UCS4"/>
...     <xsl:template match="/">
...         <foo><xsl:value-of select="/a/b/text()" /></foo>
...     </xsl:template>
... </xsl:stylesheet>''')
>>> transform = etree.XSLT(xslt_tree)

>>> result = transform(doc)
>>> unicode(result)
Traceback (most recent call last):
  [...]
LookupError: unknown encoding: UCS4

Stylesheet parameters

It is possible to pass parameters, in the form of XPath expressions, to the XSLT template:

>>> xslt_tree = etree.XML('''\
... <xsl:stylesheet version="1.0"
...     xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
...     <xsl:template match="/">
...         <foo><xsl:value-of select="$a" /></foo>
...     </xsl:template>
... </xsl:stylesheet>''')
>>> transform = etree.XSLT(xslt_tree)
>>> f = StringIO('<a><b>Text</b></a>')
>>> doc = etree.parse(f)

The parameters are passed as keyword parameters to the transform call. First let's try passing in a simple string expression:

>>> result = transform(doc, a="'A'")
>>> str(result)
'<?xml version="1.0"?>\n<foo>A</foo>\n'

Let's try a non-string XPath expression now:

>>> result = transform(doc, a="/a/b/text()")
>>> str(result)
'<?xml version="1.0"?>\n<foo>Text</foo>\n'

The xslt() tree method

There's also a convenience method on ElementTree objects for doing XSL transformations. This is less efficient if you want to apply the same XSL transformation to multiple documents, but is shorter to write for one-shot operations, as you do not have to instantiate a stylesheet yourself:

>>> result = doc.xslt(xslt_tree, a="'A'")
>>> str(result)
'<?xml version="1.0"?>\n<foo>A</foo>\n'

This is a shortcut for the following code:

>>> transform = etree.XSLT(xslt_tree)
>>> result = transform(doc, a="'A'")
>>> str(result)
'<?xml version="1.0"?>\n<foo>A</foo>\n'

Profiling

If you want to know how your stylesheet performed, pass the profile_run keyword to the transform:

>>> result = transform(doc, a="/a/b/text()", profile_run=True)
>>> profile = result.xslt_profile

The value of the xslt_profile property is an ElementTree with profiling data about each template, similar to the following:

<profile>
  <template rank="1" match="/" name="" mode="" calls="1" time="1" average="1"/>
</profile>

Note that this is a read-only document. You must not move any of its elements to other documents. Please deep-copy the document if you need to modify it. If you want to free it from memory, just do:

>>> del result.xslt_profile